The memmove function

Name

memmove -- Copy a block of memory

Synopsis

#include <string.h>

void *memmove (void *s1, void *s2, size_t n);

Description

The memmove function copies n characters from the object pointed to by s2 into the object pointed to by s1. Copying takes place as if the n characters from the object pointed to by s2 are first copied into a temporary array of n characters that does not overlap the objects pointed to by s1 and s2, and then the n characters from the temporary array are copied into the object pointed to by s1.

Returns

The memmove function returns the value of s1.

See Also

The memcpy function

Implementation Notes

None